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Physics: Fluids at Rest?

The maximum depth dmax that a diver can snorkel is set by the density of water and the fact that human lungs can function against a maximum pressure difference (between inside and outside of the chest cavity) of 0.050 atm. What is the difference in dmax for fresh water and the water of the Dead Sea? (the saltiest natural water in the world, with a density of 1.5×10^3 kg/m^3)

The answer is 17 cm, but I don’t know how to get this answer, please help!

If 1 atm is 101kpa then 5kpa is the presure limit for Snorkel breathing.
Water has a density of 1000kg/m^3 so the limit in cm would be:

(Formulae is P=h*d*g, so h=P/d*g)

Fresh
H= 5000Pa / (1000kg/m3 * 9.81m/s2) = 0.509m (51cm)

Salt in dead sea
H= 5000Pa / (1500kg/m3 * 9.81m/s2) = 0.340m (34cm)

the difference:
51-34=17cm

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One Response to “Physics: Fluids at Rest?”

  1. J D Says:

    If 1 atm is 101kpa then 5kpa is the presure limit for snorkel breathing.
    Water has a density of 1000kg/m^3 so the limit in cm would be:

    (Formulae is P=h*d*g, so h=P/d*g)

    Fresh
    H= 5000Pa / (1000kg/m3 * 9.81m/s2) = 0.509m (51cm)

    Salt in dead sea
    H= 5000Pa / (1500kg/m3 * 9.81m/s2) = 0.340m (34cm)

    the difference:
    51-34=17cm
    References :

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